blob: bb0f9cbf16ed24d1a1753a288b0da64a422741b0 [file] [log] [blame]
# Copyright (c) 1999-2008 Mark D. Hill and David A. Wood
# Copyright (c) 2009 The Hewlett-Packard Development Company
# All rights reserved.
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions are
# met: redistributions of source code must retain the above copyright
# notice, this list of conditions and the following disclaimer;
# redistributions in binary form must reproduce the above copyright
# notice, this list of conditions and the following disclaimer in the
# documentation and/or other materials provided with the distribution;
# neither the name of the copyright holders nor the names of its
# contributors may be used to endorse or promote products derived from
# this software without specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
# "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
# LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
# A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
# OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
# LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
# THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
# OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
import os
import sys
from slicc.parser import SLICC
usage = "%prog [options] <slicc file> ... "
version = "%prog v0.4"
brief_copyright = """
Copyright (c) 1999-2008 Mark D. Hill and David A. Wood
Copyright (c) 2009 The Hewlett-Packard Development Company
All Rights Reserved.
"""
help_details = """This is intended to be used to process slicc files as a
standalone script. This script assumes that it is running in a directory under
gem5/ (e.g., gem5/temp). It takes a single argument: The path to a *.slicc
file. By default it generates the C++ code in the directory generated/. This
script can also generate the html SLICC output. See src/mem/slicc/main.py for
more details."""
def nprint(format, *args):
pass
def eprint(format, *args):
if args:
format = format % args
print(format, file=sys.stderr)
def main(args=None):
import optparse
parser = optparse.OptionParser(
usage=usage,
version=version,
epilog=help_details,
description=brief_copyright,
)
parser.add_option(
"-d",
"--debug",
default=False,
action="store_true",
help="Turn on PLY debugging",
)
parser.add_option(
"-C",
"--code-path",
default="generated",
help="Path where C++ code output code goes",
)
parser.add_option("-H", "--html-path", help="Path where html output goes")
parser.add_option(
"-F",
"--print-files",
action="store_true",
help="Print files that SLICC will generate",
)
parser.add_option(
"--tb",
"--traceback",
action="store_true",
help="print traceback on error",
)
parser.add_option("-q", "--quiet", help="don't print messages")
opts, files = parser.parse_args(args=args)
if len(files) != 1:
parser.print_help()
sys.exit(2)
slicc_file = files[0]
if not slicc_file.endswith(".slicc"):
print("Must specify a .slicc file with a list of state machine files")
parser.print_help()
sys.exit(2)
output = nprint if opts.quiet else eprint
output("SLICC v0.4")
output("Parsing...")
protocol_base = os.path.join(
os.path.dirname(__file__), "..", "ruby", "protocol"
)
slicc = SLICC(
slicc_file,
protocol_base,
verbose=True,
debug=opts.debug,
traceback=opts.tb,
)
if opts.print_files:
for i in sorted(slicc.files()):
print(" %s" % i)
else:
output("Processing AST...")
slicc.process()
if opts.html_path:
output("Writing HTML files...")
slicc.writeHTMLFiles(opts.html_path)
output("Writing C++ files...")
slicc.writeCodeFiles(opts.code_path, [])
output("SLICC is Done.")
if __name__ == "__main__":
main()